How did they calculate sin(18)'s exact value?
From
2sin(18°) = 1 - 4sin^2(18°)
to
sin(18°) = (sqrt(5) - 1) / 4
I don't get how they got the sqrt(5)??
You can use this tool to write formula:
From
2sin(18°) = 1 - 4sin^2(18°)
to
sin(18°) = (sqrt(5) - 1) / 4
I don't get how they got the sqrt(5)??
You can use this tool to write formula: